Mensuration All important formulas
Mensuration Formulas For 2D Shapes
Shape | Area (Square units) | Perimeter (units) | Figure |
---|---|---|---|
Square | a2 | 4a | |
Rectangle | l × b | 2 ( l + b) | |
Circle | πr2 | 2 π r | |
Scalene Triangle | √[s(s−a)(s−b)(s−c)],
Where, s = (a+b+c)/2
| a+b+c | |
Isosceles Triangle | ½ × b × h | 2a + b | |
Equilateral Triangle | (√3/4) × a2 | 3a | |
Right Angle Triangle | ½ × b × h | b + hypotenuse + h | |
Rhombus | ½ × d1 × d2 | 4 × side | |
Parallelogram | b × h | 2(l+b) | |
Trapezium | ½ h(a+b) | a+b+c+d |
Mensuration Formulas for 3D Shapes
Shape | Volume (Cubic units) | Curved Surface Area (CSA) or Lateral Surface Area (LSA) (Square units) | Total Surface Area (TSA) (Square units) | Figure |
---|---|---|---|---|
Cube | a3 | – | 6 a2 | |
Cuboid | l × w × h | – | 2 (lb +bh +hl) | |
Sphere | (4/3) π r3 | 4 π r2 | 4 π r2 | |
Hemisphere | (⅔) π r3 | 2 π r 2 | 3 π r 2 | |
Cylinder | π r 2 h | 2π r h | 2πrh + 2πr2 | |
Cone | (⅓) π r2 h | π r l | πr (r + l) |
Mensuration Problems
Question: Find the area and perimeter of a square whose side is 5 cm?
Solution:
Given:
Side = 5 cm
Area of a square = a2 square units
Substitute the value of “a” in the formula, we get
Area of a square = 52
A = 5 x 5 = 25
A = 5 x 5 = 25
Therefore, the area of a square = 25 cm2
The perimeter of a square = 4a units
P = 4 x 5 =20
Therefore, the perimeter of a square = 20 cm.
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