Trapezoid Formula
Trapezoid Formula
The area of trapezium is the region covered by a trapezoid in a two-dimensional plane. It is the space enclosed in 2D geometry. A trapezoid is a 2D shape, which falls under the category of quadrilaterals. Trapezoid also has its own properties and trapezoid formula based on area and perimeter.
Trapezoid Formula
What is Trapezoid?
A trapezoid is a quadrilateral, which is defined as a shape with four sides and has only one set of parallel sides. Another name of a trapezoid is trapezium. A trapezium is a type of quadrilaterals, with exactly one pair of parallel sides.
The sides of a trapezoid, which are parallel to each other, are termed as the bases of the trapezoid. The non-parallel sides are known as lateral sides. The distance between the parallel sides is known as the altitude.
Properties of a Trapezoid
In a trapezium, the sum of all the four angles of the trapezium is equal to 3600. A Trapezium has 4 unequal sides. A Trapezium has two parallel sides and two non-parallel sides. The diagonals of trapezium bisect each other. The intersection point of the diagonals is collinear to the midpoints of the two opposite sides.
Area of a Trapezium
We can calculate the area of trapezium by using the formula:
Area = 12 × (sum of parallel sides) × (distance between them) = 12h(a+b)
Where,
h | Distance Between Parallel Lines |
a, b | Length of parallel sides |
Derivation of Area of a Trapezium
The area of a trapezium is equal to the sum of the areas of the two triangles and the area of the rectangle.
We know that
Area of trapezium ABCD = Area of ∆ AED + Area of ∆ BFC + Area of rectangle DEFC
= (12×AE×DE)+(12×FB×CF)+(FE×DE)
= (12×AE×h)+(12×FB×h)+(FE×h)
= 12×h×(AE+2FE+FB)
= 12×h×(AE+FE+EB+FE)
So,
= 12×h×(AB+FE)
= 12 × h × (AB + DC) square units.
= 12 × (sum of parallel sides) × (distance between them)
The perimeter of a Trapezium
Perimeter of a trapezium is the sum of all sides of the trapezium.
Perimeter of trapezium PQRS = PQ + RS + QR + RP
Solved Examples
Q.1. The length of the parallel sides of a trapezium is in the ratio 3: 2 and the distance between them is 10 cm. If the area of trapezium is 325 cm², find the length of the parallel sides.
Solution: Let the common ration be x,
Then the two parallel sides are 3x, 2x
Distance between them = 10 cm
Area of trapezium = 325 cm²
Area of trapezium = 12h(a+b)
325 = 12(3x+2x)×10
i.e. 325 = 5 × x × 5
⇒ 325 = 25 ͯ x
⇒ x = 32525
Therefore, 3 ͯ x = 3 ͯ 13 = 39 and 2 ͯ x = 2 ͯ 13 = 26
Length of parallel sides are 26 cm and 39 cm.
Q.2. Find the area of a trapezium with bases of 6 meters and 4 meters and a height of 3 meters.
Solution: Area of trapezium = 12h(a+b)
Area = (6+4)ͯ32
Area = 15 m2
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